若a-b=2,a-c=1,则(2a-b-c)^2+(c-b)^2的值为?
若a-b=2,a-c=1,则(2a-b-c)^2+(c-b)^2的值为?
参考答案:(2a-b-c)^2+(c-b)^2
=(a-b+a-c)^2+[(a-b)-(a-c)]^2
=(2+1)^2+(2-1)^2
=3^2+1^2
=9+1
=10
若a-b=2,a-c=1,则(2a-b-c)^2+(c-b)^2的值为?
参考答案:(2a-b-c)^2+(c-b)^2
=(a-b+a-c)^2+[(a-b)-(a-c)]^2
=(2+1)^2+(2-1)^2
=3^2+1^2
=9+1
=10