证明不等式1/log5(19)+2/log3(19)+3/log2(19)<2. 高手们,拜托了!
1/log5(19)+2/log3(19)+3/log2(19)=log19(5)+log19(3^2)+log19(2^3)=log19(5*9*8)=log19(360)<log19(361)=2
1/log5(19)+2/log3(19)+3/log2(19)=log19(5)+log19(3^2)+log19(2^3)=log19(5*9*8)=log19(360)<log19(361)=2