分解因式(x-1)(x-2)(x+2)(x+3)-60,遇到了难题,请大家帮帮忙
数学题,会的速回,多谢了!!!!
参考答案:(x-1)(x-2)(x+2)(x+3)-60
=[(x-1)(x+2)][(x-2)(x+3)]-60
=[x^2+x-2][x^2+x-6]-60
=[x^2+x]^2-8[x^2+x]-48
=[x^2+x-12][x^2+x+4]
=(x+4)(x-3)(x^2+x+4)
数学题,会的速回,多谢了!!!!
参考答案:(x-1)(x-2)(x+2)(x+3)-60
=[(x-1)(x+2)][(x-2)(x+3)]-60
=[x^2+x-2][x^2+x-6]-60
=[x^2+x]^2-8[x^2+x]-48
=[x^2+x-12][x^2+x+4]
=(x+4)(x-3)(x^2+x+4)