用配方法解下列方程(写出过程)
4X2-45=31X
-3X2+22X-24=0
(3X+2)(X+3)=X+14
2(X+3)2=X(X+3)
(X+1)2-3(X+1)+2=0
参考答案:4X2-45=31X
x^2-31/4x=45/4
[x-31/8]^2=45/4+961/64=1681/64
x-31/8=+/-41/8
x1=31/8+41/8=9
x2=-41/8+31/8=-5/4
-3X2+22X-24=0
x^2-22/3x+8=0
[x-11/3]^2=49/9
x-11/3=+/-7/3
x1=11/3+7/3=6
x2=11/3-7/3=4/3
(3X+2)(X+3)=X+14
3x^2+11x+6=x+14
3x^2+10x=8
x^2+10/3x=8/3
[x+5/3]^2=49/9
x+5/3=+/-7/3
x1=-5/3+7/3=2/3
x2=-5/3-7/3=-4
2(X+3)2=X(X+3)
2x^2+12x+18=x^2+3x
x^2+9x+18=0
[x+9/2]^2=9/4
x+9/2=+/-3/2
x1=-9/2+3/2=-3
x2=-9/2-3/2=-6
(X+1)2-3(X+1)+2=0
x^2+2x+1-3x-3+2=0
x^2-x=0
[x-1/2]^2=1/4
x-1/2=+/-1/2
x1=1/2+1/2=1
x2=1/2-1/2=0