初二数学题!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
若xxx+5xx+3x+m有一个因式x-1,求m值,并将原式进行因式分解.
(xxx代表x的三次方,xx代表x的平方)
参考答案:x^3+5x^2+3x+m有因式x-1
则x=1时 x^3+5x^2+3x+m=0
m=-9
x^3+5x^2+3x-9
=x^2(x-1)+6x(x-1)+9(x-1)
=(x+3)^2*(x-1)
若xxx+5xx+3x+m有一个因式x-1,求m值,并将原式进行因式分解.
(xxx代表x的三次方,xx代表x的平方)
参考答案:x^3+5x^2+3x+m有因式x-1
则x=1时 x^3+5x^2+3x+m=0
m=-9
x^3+5x^2+3x-9
=x^2(x-1)+6x(x-1)+9(x-1)
=(x+3)^2*(x-1)