一道数学题 帮忙! thanks
比较大小
(x+y)/2与(2xy)/(x+y)
作差
两个式子都大于0
参考答案:(x+y)/2-(2xy)/(x+y)
=[(x+y)^2-(4xy)]/2(x+y)
=[x^2+2xy+y^2-4xy]/2(x+y)
=[x^2-2xy+y^2]/2(x+y)
=(x-y)^2/2(x+y)
两个式子都大于0
(x+y)/2>0
x+y>0
(x-y)^2>=0
(x+y)/2>=(2xy)/(x+y)
(x-y)^2/2(x+y)>=0
比较大小
(x+y)/2与(2xy)/(x+y)
作差
两个式子都大于0
参考答案:(x+y)/2-(2xy)/(x+y)
=[(x+y)^2-(4xy)]/2(x+y)
=[x^2+2xy+y^2-4xy]/2(x+y)
=[x^2-2xy+y^2]/2(x+y)
=(x-y)^2/2(x+y)
两个式子都大于0
(x+y)/2>0
x+y>0
(x-y)^2>=0
(x+y)/2>=(2xy)/(x+y)
(x-y)^2/2(x+y)>=0