初二数学题!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
(2√2-3)^2001(2√2-3)^2003
参考答案:题目应该是这样的吧:
(2√2-3)^2001(2√2+3)^2003
=[2根2-3]^2001*[2根2+3]^2001*[2根2+3]^2
=[(2根2-3)(2根2+3)]^2001*[2根2+3]^2
=[8-9]^2001*[8+9+12根2]
=-(17+12根2)
(2√2-3)^2001(2√2-3)^2003
参考答案:题目应该是这样的吧:
(2√2-3)^2001(2√2+3)^2003
=[2根2-3]^2001*[2根2+3]^2001*[2根2+3]^2
=[(2根2-3)(2根2+3)]^2001*[2根2+3]^2
=[8-9]^2001*[8+9+12根2]
=-(17+12根2)