已知a的4次方+A的3次方+A的2次方+A+1=0,则A的1995次方+A的2000次方+2002=
麻烦 麻烦
参考答案:(a-1)(a^4 + a^3 + a^2 + a^1 + 1) = a^5 - 1 = 0
a^5 = 1
a^1995 + a^2000 + 2002 = 1 + 1 + 2002 = 2004
麻烦 麻烦
参考答案:(a-1)(a^4 + a^3 + a^2 + a^1 + 1) = a^5 - 1 = 0
a^5 = 1
a^1995 + a^2000 + 2002 = 1 + 1 + 2002 = 2004