php查询mysql的sql语句问题
mysql_select_db("icezwing");
$result=mysql_query("select top 2 * from message");
131 $answer=mysql_fetch_array($result);
mysql_close($db);
return $answer;
出错提示:Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource
参考答案:$result=mysql_query(\"select top 2 * from message\");
改成 $result=mysql_query(\"select * from message limit 0,2\");