初二分式计算
x+2/x+1 - x+3/x+2 - x-4/x-3 + x-5/x-4
参考答案:x+2/x+1 =1+ 1/x+1
x+3/x+2=1+ 1/x+2
x-4/x-3=1- 1/x-3
x-5/x-4=1- 1/x-4
代入,得
1/x-3 -1/x-4 +1/x+1 - 1/x+2
= 1/(x+1)(x+2)-1/(x-3)(x-4)
=10-10x/(x*x-2x-3)(x*x-2x-8)
=10-10x/(x*x*x*x-4X*X*X+9x*x+22x+24)
x+2/x+1 - x+3/x+2 - x-4/x-3 + x-5/x-4
参考答案:x+2/x+1 =1+ 1/x+1
x+3/x+2=1+ 1/x+2
x-4/x-3=1- 1/x-3
x-5/x-4=1- 1/x-4
代入,得
1/x-3 -1/x-4 +1/x+1 - 1/x+2
= 1/(x+1)(x+2)-1/(x-3)(x-4)
=10-10x/(x*x-2x-3)(x*x-2x-8)
=10-10x/(x*x*x*x-4X*X*X+9x*x+22x+24)