问一到数学计算题,帮忙啊!!
解方程;[(X+1)(X-1)-(x-1)(x^2+x+1)]/x^2=1/3X.
参考答案:[(X+1)(X-1)-(x-1)(x^2+x+1)]/x^2=1/3X
[x^2-1-(x^3+x^2+x)+x^2+x+1]/x^2=x/3
x^2-x^3=x^3/3
x^2=4x^3/3
x=3/4
解方程;[(X+1)(X-1)-(x-1)(x^2+x+1)]/x^2=1/3X.
参考答案:[(X+1)(X-1)-(x-1)(x^2+x+1)]/x^2=1/3X
[x^2-1-(x^3+x^2+x)+x^2+x+1]/x^2=x/3
x^2-x^3=x^3/3
x^2=4x^3/3
x=3/4