初三数学题
[1-2/(x+1)]^2÷(x-1)/(x+1)请写明步骤
参考答案:[1-2/(x+1)]^2÷(x-1)/(x+1)
=[(x+1-2)/(x+1)]^2*(x+1)/(x-1)
=[(x-1)^2/(x+1)^2]*(x+1)/(x-1)
=(x-1)/(x+1)
[1-2/(x+1)]^2÷(x-1)/(x+1)请写明步骤
参考答案:[1-2/(x+1)]^2÷(x-1)/(x+1)
=[(x+1-2)/(x+1)]^2*(x+1)/(x-1)
=[(x-1)^2/(x+1)^2]*(x+1)/(x-1)
=(x-1)/(x+1)