如果代数式ax^5+bx^3+cx-5在x=-2时的值是7,那么当x=2时,该式的值是多少?
帮我写一下过程谢谢?
参考答案:a[-2]^5+b[-2]^3+c[-2]-5
=-a2^5-b2^3-c2-5
=-[a2^5+b2^3+c2-5]-10
=7
a2^5+b2^3+c2-5=-17
帮我写一下过程谢谢?
参考答案:a[-2]^5+b[-2]^3+c[-2]-5
=-a2^5-b2^3-c2-5
=-[a2^5+b2^3+c2-5]-10
=7
a2^5+b2^3+c2-5=-17