有一道因式分解希望大家帮我做一下!
x(x+1)(x-2)(x-3)-4
(是初一的题目)
参考答案:原式=x(x-2)(x+1)(x-3)-4
=(x^2-2x)(x^2-2x-3)-4
=(x^2-2x)^2-3(x^2-2x)-4
=(x^2-2x-4)(x^2-2x+1)
=(x^2-2x-4)(x-1)^2
x(x+1)(x-2)(x-3)-4
(是初一的题目)
参考答案:原式=x(x-2)(x+1)(x-3)-4
=(x^2-2x)(x^2-2x-3)-4
=(x^2-2x)^2-3(x^2-2x)-4
=(x^2-2x-4)(x^2-2x+1)
=(x^2-2x-4)(x-1)^2