数学题!!
1+3+5+7+```+(2n-1)=???
1+3+5+7+```+(2n+1)=???
参考答案:1+3+5+7+```+(2n-1)
=[(1+2n-1)^/2]^2
=n^2
1+3+5+7+```+(2n+1)
=[(1+2n+1)^/2]^2
=(n+1)^2
1+3+5+7+```+(2n-1)=???
1+3+5+7+```+(2n+1)=???
参考答案:1+3+5+7+```+(2n-1)
=[(1+2n-1)^/2]^2
=n^2
1+3+5+7+```+(2n+1)
=[(1+2n+1)^/2]^2
=(n+1)^2