1-1/2+1/3-1/4+……+1/99-1/100
S1: sigh=1
S2: sum=1
S3: deno=2
S4: sigh=(-1)×sigh
S5: term= sigh×(1/deno )
S6: term=sum+term
S7: deno= deno +1
S8:若deno≤100，返回S4；否则，结束。
每句话的意思！~~
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参考答案:上面的算法，如果用C来做，程序应该是下面的代码：
main()
{
int i;
float sum=1,sign;
for(i = 2; i <= 100; i++)
{
sign = -1.0 / i;
sum += sign;
}
printf("the summation is %f\n",sum);
getch();
}